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(x+4)^(1/2)-4x=4
We move all terms to the left:
(x+4)^(1/2)-4x-(4)=0
We add all the numbers together, and all the variables
(x+4)^(+1/2)-4x-4=0
We add all the numbers together, and all the variables
-4x+(x+4)^(+1/2)-4=0
We multiply all the terms by the denominator
-4x*2)+(x+1+4)^(-4*2)=0
We add all the numbers together, and all the variables
-4x*2)+(x+5)^(-8)=0
We add all the numbers together, and all the variables
-4x*2)+(x=0
Wy multiply elements
-8x^2=0
a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-16}=0$
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